4/(x+5)+2/(x-5)=32/x^2-25

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Solution for 4/(x+5)+2/(x-5)=32/x^2-25 equation: 



4/(x+5)+2/(x-5)=32/x^2-25

We move all terms to the left:

4/(x+5)+2/(x-5)-(32/x^2-25)=0



Domain of the equation: (x+5)!=0

We move all terms containing x to the left, all other terms to the right

x!=-5

x∈R





Domain of the equation: (x-5)!=0

We move all terms containing x to the left, all other terms to the right

x!=5

x∈R





Domain of the equation: x^2-25)!=0

x∈R



We get rid of parentheses

4/(x+5)+2/(x-5)-32/x^2+25=0

We calculate fractions


(4*(x-5)*x^2)/((x+5)*(x-5)*x^2)+(2*(x+5)*x^2)/((x+5)*(x-5)*x^2)+(-32*(x+5)*(x-5))/((x+5)*(x-5)*x^2)+25=0



We calculate terms in parentheses: +(4*(x-5)*x^2)/((x+5)*(x-5)*x^2), so:

4*(x-5)*x^2)/((x+5)*(x-5)*x^2

We multiply all the terms by the denominator


4*(x-5)*x^2)

We multiply parentheses

-20x^3+4x

We do not support expression: x^3

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